Base | Representation |
---|---|
bin | 11000111010000100100… |
… | …100111000100111111010 |
3 | 20001121222211100020222112 |
4 | 120322010210320213322 |
5 | 211020400014323214 |
6 | 3350150303252322 |
7 | 234442366351412 |
oct | 30720444704772 |
9 | 6047884306875 |
10 | 1711621245434 |
11 | 5aa992631261 |
12 | 2378825aa0a2 |
13 | c5536286c69 |
14 | 5cbb2d35642 |
15 | 2e7cabc5a3e |
hex | 18e849389fa |
1711621245434 has 4 divisors (see below), whose sum is σ = 2567431868154. Its totient is φ = 855810622716.
The previous prime is 1711621245427. The next prime is 1711621245461. The reversal of 1711621245434 is 4345421261171.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 938180148409 + 773441097025 = 968597^2 + 879455^2 .
It is a super-3 number, since 3×17116212454343 (a number of 38 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1711621245391 and 1711621245400.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 427905311357 + ... + 427905311360.
Almost surely, 21711621245434 is an apocalyptic number.
1711621245434 is a deficient number, since it is larger than the sum of its proper divisors (855810622720).
1711621245434 is an equidigital number, since it uses as much as digits as its factorization.
1711621245434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 855810622719.
The product of its digits is 161280, while the sum is 41.
The spelling of 1711621245434 in words is "one trillion, seven hundred eleven billion, six hundred twenty-one million, two hundred forty-five thousand, four hundred thirty-four".
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