1711983343 has 4 divisors (see below), whose sum is σ = 1956552400. Its totient is φ = 1467414288.

The previous prime is 1711983341. The next prime is 1711983367. The reversal of 1711983343 is 3433891171.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3433891171 = 163 ⋅21066817.

It is a cyclic number.

It is not a de Polignac number, because 1711983343 - 2¹ = 1711983341 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1711983296 and 1711983305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1711983341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 122284518 + ... + 122284531.

It is an arithmetic number, because the mean of its divisors is an integer number (489138100).

Almost surely, 2^1711983343 is an apocalyptic number.

1711983343 is a deficient number, since it is larger than the sum of its proper divisors (244569057).

1711983343 is an equidigital number, since it uses as much as digits as its factorization.

1711983343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 244569056.

The product of its digits is 54432, while the sum is 40.

The square root of 1711983343 is about 41376.1204440436. The cubic root of 1711983343 is about 1196.2809261582.

The spelling of 1711983343 in words is "one billion, seven hundred eleven million, nine hundred eighty-three thousand, three hundred forty-three".