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1712113435405 = 519791027316843
BaseRepresentation
bin11000111010100001111…
…010011100001100001101
320001200021010111002200201
4120322201322130030031
5211022402014413110
63350311204453501
7234460524036532
oct30724172341415
96050233432621
101712113435405
1160011544392a
1223799b3aa291
13c55b4236229
145cc1c456d89
152e808ee9b3a
hex18ea1e9c30d

1712113435405 has 16 divisors (see below), whose sum is σ = 2055896441280. Its totient is φ = 1368784101888.

The previous prime is 1712113435397. The next prime is 1712113435411. The reversal of 1712113435405 is 5045343112171.

It is a cyclic number.

It is not a de Polignac number, because 1712113435405 - 23 = 1712113435397 is a prime.

It is a super-2 number, since 2×17121134354052 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 101642914 + ... + 101659756.

It is an arithmetic number, because the mean of its divisors is an integer number (128493527580).

Almost surely, 21712113435405 is an apocalyptic number.

It is an amenable number.

1712113435405 is a deficient number, since it is larger than the sum of its proper divisors (343783005875).

1712113435405 is a wasteful number, since it uses less digits than its factorization.

1712113435405 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29100.

The product of its (nonzero) digits is 50400, while the sum is 37.

Adding to 1712113435405 its reverse (5045343112171), we get a palindrome (6757456547576).

The spelling of 1712113435405 in words is "one trillion, seven hundred twelve billion, one hundred thirteen million, four hundred thirty-five thousand, four hundred five".

Divisors: 1 5 1979 9895 10273 16843 51365 84215 20330267 33332297 101651335 166661485 173028139 865140695 342422687081 1712113435405