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17130424213 = 72447203459
BaseRepresentation
bin11111111010000110…
…11000011110010101
31122012211220201022001
433331003120132111
5240040342033323
611511500235301
71144336126510
oct177503303625
948184821261
1017130424213
1172a0750291
1233a0b3bb31
131800029cb6
14b8714dd77
156a3d8b3ad
hex3fd0d8795

17130424213 has 4 divisors (see below), whose sum is σ = 19577627680. Its totient is φ = 14683220748.

The previous prime is 17130424163. The next prime is 17130424231. The reversal of 17130424213 is 31242403171.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2k-17130424213 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (17130424273) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1223601723 + ... + 1223601736.

It is an arithmetic number, because the mean of its divisors is an integer number (4894406920).

Almost surely, 217130424213 is an apocalyptic number.

It is an amenable number.

17130424213 is a deficient number, since it is larger than the sum of its proper divisors (2447203467).

17130424213 is an equidigital number, since it uses as much as digits as its factorization.

17130424213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2447203466.

The product of its (nonzero) digits is 4032, while the sum is 28.

Adding to 17130424213 its reverse (31242403171), we get a palindrome (48372827384).

The spelling of 17130424213 in words is "seventeen billion, one hundred thirty million, four hundred twenty-four thousand, two hundred thirteen".

Divisors: 1 7 2447203459 17130424213