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17130541 = 130313147
BaseRepresentation
bin100000101011…
…0010000101101
31012020022200111
41001112100231
513341134131
61411100021
7265415161
oct101262055
935208614
1017130541
11974047a
1258a1611
13371a31c
1423bcca1
151785ab1
hex105642d

17130541 has 4 divisors (see below), whose sum is σ = 17144992. Its totient is φ = 17116092.

The previous prime is 17130539. The next prime is 17130551. The reversal of 17130541 is 14503171.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14503171 = 83174737.

It is a cyclic number.

It is not a de Polignac number, because 17130541 - 21 = 17130539 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (17130551) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5271 + ... + 7876.

It is an arithmetic number, because the mean of its divisors is an integer number (4286248).

Almost surely, 217130541 is an apocalyptic number.

It is an amenable number.

17130541 is a deficient number, since it is larger than the sum of its proper divisors (14451).

17130541 is a wasteful number, since it uses less digits than its factorization.

17130541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14450.

The product of its (nonzero) digits is 420, while the sum is 22.

The square root of 17130541 is about 4138.9057732691. The cubic root of 17130541 is about 257.7846338856.

It can be divided in two parts, 17130 and 541, that added together give a palindrome (17671).

The spelling of 17130541 in words is "seventeen million, one hundred thirty thousand, five hundred forty-one".

Divisors: 1 1303 13147 17130541