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17131423 = 61280843
BaseRepresentation
bin100000101011…
…0011110011111
31012020100220011
41001112132133
513341201143
61411104051
7265420561
oct101263637
935210804
1017131423
119741101
1258a2027
13371a84a
1423bd331
151785e9d
hex105679f

17131423 has 4 divisors (see below), whose sum is σ = 17412328. Its totient is φ = 16850520.

The previous prime is 17131409. The next prime is 17131441. The reversal of 17131423 is 32413171.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32413171 = 74630453.

It is a cyclic number.

It is not a de Polignac number, because 17131423 - 25 = 17131391 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 17131394 and 17131403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (17131123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 140361 + ... + 140482.

It is an arithmetic number, because the mean of its divisors is an integer number (4353082).

Almost surely, 217131423 is an apocalyptic number.

17131423 is a deficient number, since it is larger than the sum of its proper divisors (280905).

17131423 is an equidigital number, since it uses as much as digits as its factorization.

17131423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 280904.

The product of its digits is 504, while the sum is 22.

The square root of 17131423 is about 4139.0123217985. The cubic root of 17131423 is about 257.7890579947.

Adding to 17131423 its reverse (32413171), we get a palindrome (49544594).

It can be divided in two parts, 1713 and 1423, that added together give a square (3136 = 562).

The spelling of 17131423 in words is "seventeen million, one hundred thirty-one thousand, four hundred twenty-three".

Divisors: 1 61 280843 17131423