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17140052113 = 463154923899
BaseRepresentation
bin11111111011010000…
…00111000010010001
31122020112000212021221
433331220013002101
5240100323131423
611512442445041
71144514016262
oct177550070221
948215025257
1017140052113
1172a6126928
1233a4203781
13180201b392
14b88538969
156a4b3de5d
hex3fda07091

17140052113 has 8 divisors (see below), whose sum is σ = 17188880000. Its totient is φ = 17091276048.

The previous prime is 17140052107. The next prime is 17140052131. The reversal of 17140052113 is 31125004171.

17140052113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 17140052113 - 221 = 17137954961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (17140052213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 705238 + ... + 729136.

It is an arithmetic number, because the mean of its divisors is an integer number (2148610000).

Almost surely, 217140052113 is an apocalyptic number.

It is an amenable number.

17140052113 is a deficient number, since it is larger than the sum of its proper divisors (48827887).

17140052113 is a wasteful number, since it uses less digits than its factorization.

17140052113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25911.

The product of its (nonzero) digits is 840, while the sum is 25.

Adding to 17140052113 its reverse (31125004171), we get a palindrome (48265056284).

The spelling of 17140052113 in words is "seventeen billion, one hundred forty million, fifty-two thousand, one hundred thirteen".

Divisors: 1 463 1549 23899 717187 11065237 37019551 17140052113