1745012113 has 4 divisors (see below), whose sum is σ = 1879243828. Its totient is φ = 1610780400.

The previous prime is 1745012077. The next prime is 1745012123. The reversal of 1745012113 is 3112105471.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 328769424 + 1416242689 = 18132^2 + 37633^2 .

It is a cyclic number.

It is not a de Polignac number, because 1745012113 - 2⁹ = 1745011601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1745012123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67115838 + ... + 67115863.

It is an arithmetic number, because the mean of its divisors is an integer number (469810957).

Almost surely, 2^1745012113 is an apocalyptic number.

1745012113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1745012113 is a deficient number, since it is larger than the sum of its proper divisors (134231715).

1745012113 is a wasteful number, since it uses less digits than its factorization.

1745012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 134231714.

The product of its (nonzero) digits is 840, while the sum is 25.

The square root of 1745012113 is about 41773.3421334707. The cubic root of 1745012113 is about 1203.9251362100.

Adding to 1745012113 its reverse (3112105471), we get a palindrome (4857117584).

The spelling of 1745012113 in words is "one billion, seven hundred forty-five million, twelve thousand, one hundred thirteen".