Base | Representation |
---|---|
bin | 10000111000011101… |
… | …100010000000000000 |
3 | 1201210022101212002000 |
4 | 100320131202000000 |
5 | 244111021302340 |
6 | 12154423224000 |
7 | 1211131050162 |
oct | 207035420000 |
9 | 51708355060 |
10 | 18127134720 |
11 | 7762327682 |
12 | 361a8a8000 |
13 | 192b684b26 |
14 | c3d682932 |
15 | 71161cd30 |
hex | 438762000 |
18127134720 has 448 divisors, whose sum is σ = 66339354240. Its totient is φ = 4692639744.
The previous prime is 18127134709. The next prime is 18127134721. The reversal of 18127134720 is 2743172181.
18127134720 is a `hidden beast` number, since 181 + 2 + 7 + 1 + 3 + 472 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (36).
It is not an unprimeable number, because it can be changed into a prime (18127134721) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 40918819 + ... + 40919261.
Almost surely, 218127134720 is an apocalyptic number.
18127134720 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 18127134720, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (33169677120).
18127134720 is an abundant number, since it is smaller than the sum of its proper divisors (48212219520).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
18127134720 is an equidigital number, since it uses as much as digits as its factorization.
18127134720 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 520 (or 490 counting only the distinct ones).
The product of its (nonzero) digits is 18816, while the sum is 36.
The spelling of 18127134720 in words is "eighteen billion, one hundred twenty-seven million, one hundred thirty-four thousand, seven hundred twenty".
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