18289114906453 has 4 divisors (see below), whose sum is σ = 18289123532748. Its totient is φ = 18289106280160.

The previous prime is 18289114906429. The next prime is 18289114906481. The reversal of 18289114906453 is 35460941198281.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 7943930976004 + 10345183930449 = 2818498^2 + 3216393^2 .

It is a cyclic number.

It is not a de Polignac number, because 18289114906453 - 2⁴¹ = 16090091650901 is a prime.

It is a super-2 number, since 2×18289114906453² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 18289114906391 and 18289114906400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (18289114900453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1315875 + ... + 6189487.

It is an arithmetic number, because the mean of its divisors is an integer number (4572280883187).

Almost surely, 2^{18289114906453} is an apocalyptic number.

It is an amenable number.

18289114906453 is a deficient number, since it is larger than the sum of its proper divisors (8626295).

18289114906453 is an equidigital number, since it uses as much as digits as its factorization.

18289114906453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8626294.

The product of its (nonzero) digits is 14929920, while the sum is 61.

The spelling of 18289114906453 in words is "eighteen trillion, two hundred eighty-nine billion, one hundred fourteen million, nine hundred six thousand, four hundred fifty-three".