Base | Representation |
---|---|
bin | 10001011000100001… |
… | …000110111101001011 |
3 | 1210011210101100221022 |
4 | 101120201012331023 |
5 | 301211211142220 |
6 | 12324034303055 |
7 | 1230351254465 |
oct | 213041067513 |
9 | 53153340838 |
10 | 18664943435 |
11 | 7a08968296 |
12 | 374aa27a8b |
13 | 19b5c17238 |
14 | c90c7b135 |
15 | 743953925 |
hex | 458846f4b |
18664943435 has 4 divisors (see below), whose sum is σ = 22397932128. Its totient is φ = 14931954744.
The previous prime is 18664943389. The next prime is 18664943449. The reversal of 18664943435 is 53434946681.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53434946681 = 32941 ⋅1622141.
It is a cyclic number.
It is not a de Polignac number, because 18664943435 - 212 = 18664939339 is a prime.
It is a super-3 number, since 3×186649434353 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1866494339 + ... + 1866494348.
It is an arithmetic number, because the mean of its divisors is an integer number (5599483032).
Almost surely, 218664943435 is an apocalyptic number.
18664943435 is a deficient number, since it is larger than the sum of its proper divisors (3732988693).
18664943435 is an equidigital number, since it uses as much as digits as its factorization.
18664943435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3732988692.
The product of its digits is 7464960, while the sum is 53.
The spelling of 18664943435 in words is "eighteen billion, six hundred sixty-four million, nine hundred forty-three thousand, four hundred thirty-five".
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