Base | Representation |
---|---|
bin | 10001110110110110… |
… | …110011111111000101 |
3 | 1211111021011112211101 |
4 | 101312312303333011 |
5 | 303232012340011 |
6 | 12450340140101 |
7 | 1246101611026 |
oct | 216666637705 |
9 | 54437145741 |
10 | 19173949381 |
11 | 814a215a64 |
12 | 3871397631 |
13 | 1a675035a2 |
14 | cdc6d8c4d |
15 | 77349a2c1 |
hex | 476db3fc5 |
19173949381 has 4 divisors (see below), whose sum is σ = 19205026092. Its totient is φ = 19142872672.
The previous prime is 19173949369. The next prime is 19173949391. The reversal of 19173949381 is 18394937191.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 237437281 + 18936512100 = 15409^2 + 137610^2 .
It is a cyclic number.
It is not a de Polignac number, because 19173949381 - 25 = 19173949349 is a prime.
It is a super-2 number, since 2×191739493812 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (19173949331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15537430 + ... + 15538663.
It is an arithmetic number, because the mean of its divisors is an integer number (4801256523).
Almost surely, 219173949381 is an apocalyptic number.
It is an amenable number.
19173949381 is a deficient number, since it is larger than the sum of its proper divisors (31076711).
19173949381 is an equidigital number, since it uses as much as digits as its factorization.
19173949381 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31076710.
The product of its digits is 1469664, while the sum is 55.
The spelling of 19173949381 in words is "nineteen billion, one hundred seventy-three million, nine hundred forty-nine thousand, three hundred eighty-one".
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