1941402531311 has 4 divisors (see below), whose sum is σ = 1986551427432. Its totient is φ = 1896253635192.

The previous prime is 1941402531287. The next prime is 1941402531319. The reversal of 1941402531311 is 1131352041491.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1941402531311 - 2¹⁸ = 1941402269167 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1941402531319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22574447996 + ... + 22574448081.

It is an arithmetic number, because the mean of its divisors is an integer number (496637856858).

Almost surely, 2^{1941402531311} is an apocalyptic number.

1941402531311 is a deficient number, since it is larger than the sum of its proper divisors (45148896121).

1941402531311 is an equidigital number, since it uses as much as digits as its factorization.

1941402531311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45148896120.

The product of its (nonzero) digits is 12960, while the sum is 35.

The spelling of 1941402531311 in words is "one trillion, nine hundred forty-one billion, four hundred two million, five hundred thirty-one thousand, three hundred eleven".