Base | Representation |
---|---|
bin | 1000110110100110100111… |
… | …10010111010100011110111 |
3 | 2112221011012110000112110120 |
4 | 10123103103302322203313 |
5 | 10022432132323000421 |
6 | 105223345001023023 |
7 | 4046353512113241 |
oct | 433232362724367 |
9 | 75834173015416 |
10 | 19468345125111 |
11 | 622652a314613 |
12 | 2225119484a73 |
13 | ab2b1ac93b7c |
14 | 4b43b6cd3091 |
15 | 23b63a1da8c6 |
hex | 11b4d3cba8f7 |
19468345125111 has 4 divisors (see below), whose sum is σ = 25957793500152. Its totient is φ = 12978896750072.
The previous prime is 19468345125067. The next prime is 19468345125161. The reversal of 19468345125111 is 11152154386491.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 19468345125111 - 27 = 19468345124983 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (19468345125161) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3244724187516 + ... + 3244724187521.
It is an arithmetic number, because the mean of its divisors is an integer number (6489448375038).
Almost surely, 219468345125111 is an apocalyptic number.
19468345125111 is a deficient number, since it is larger than the sum of its proper divisors (6489448375041).
19468345125111 is an equidigital number, since it uses as much as digits as its factorization.
19468345125111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6489448375040.
The product of its digits is 1036800, while the sum is 51.
The spelling of 19468345125111 in words is "nineteen trillion, four hundred sixty-eight billion, three hundred forty-five million, one hundred twenty-five thousand, one hundred eleven".
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