1953493151 has 4 divisors (see below), whose sum is σ = 2056308600. Its totient is φ = 1850677704.

The previous prime is 1953493121. The next prime is 1953493153. The reversal of 1953493151 is 1513943591.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1513943591 = 67 ⋅22596173.

It is a cyclic number.

It is not a de Polignac number, because 1953493151 - 2¹⁰ = 1953492127 is a prime.

It is a super-2 number, since 2×1953493151² = 7632270982007817602, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1953493099 and 1953493108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1953493153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51407696 + ... + 51407733.

It is an arithmetic number, because the mean of its divisors is an integer number (514077150).

Almost surely, 2^1953493151 is an apocalyptic number.

1953493151 is a deficient number, since it is larger than the sum of its proper divisors (102815449).

1953493151 is a wasteful number, since it uses less digits than its factorization.

1953493151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 102815448.

The product of its digits is 72900, while the sum is 41.

The square root of 1953493151 is about 44198.3387809995. The cubic root of 1953493151 is about 1250.0785339458.

The spelling of 1953493151 in words is "one billion, nine hundred fifty-three million, four hundred ninety-three thousand, one hundred fifty-one".