Base | Representation |
---|---|
bin | 11100100110000100100… |
… | …100101000100100100011 |
3 | 20221212001220210122222101 |
4 | 130212010210220210203 |
5 | 224143332202001042 |
6 | 4102415241151231 |
7 | 261653063351620 |
oct | 34460444504443 |
9 | 6855056718871 |
10 | 1965024250147 |
11 | 6983a8a632a2 |
12 | 278a0278b517 |
13 | 1133bb3814ba |
14 | 6b171697347 |
15 | 361ac63c6b7 |
hex | 1c984928923 |
1965024250147 has 16 divisors (see below), whose sum is σ = 2326803148800. Its totient is φ = 1623914601120.
The previous prime is 1965024250109. The next prime is 1965024250159. The reversal of 1965024250147 is 7410524205691.
It is a de Polignac number, because none of the positive numbers 2k-1965024250147 is a prime.
It is a super-4 number, since 4×19650242501474 (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1965024250097 and 1965024250106.
It is not an unprimeable number, because it can be changed into a prime (1965024250547) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16773247 + ... + 16889992.
It is an arithmetic number, because the mean of its divisors is an integer number (145425196800).
Almost surely, 21965024250147 is an apocalyptic number.
1965024250147 is a deficient number, since it is larger than the sum of its proper divisors (361778898653).
1965024250147 is a wasteful number, since it uses less digits than its factorization.
1965024250147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33663546.
The product of its (nonzero) digits is 604800, while the sum is 46.
The spelling of 1965024250147 in words is "one trillion, nine hundred sixty-five billion, twenty-four million, two hundred fifty thousand, one hundred forty-seven".
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