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196520017413 = 365506672471
BaseRepresentation
bin1011011100000110000…
…0010111111000000101
3200210020211002020211110
42313001200113320011
511204433111024123
6230140253555233
720124643405116
oct2670140277005
9623224066743
10196520017413
1176386476835
12321061a5b19
13156bb370b95
149723c5420d
1551a2bbd493
hex2dc1817e05

196520017413 has 4 divisors (see below), whose sum is σ = 262026689888. Its totient is φ = 131013344940.

The previous prime is 196520017411. The next prime is 196520017429. The reversal of 196520017413 is 314710025691.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 196520017413 - 21 = 196520017411 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (196520017411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32753336233 + ... + 32753336238.

It is an arithmetic number, because the mean of its divisors is an integer number (65506672472).

Almost surely, 2196520017413 is an apocalyptic number.

It is an amenable number.

196520017413 is a deficient number, since it is larger than the sum of its proper divisors (65506672475).

196520017413 is an equidigital number, since it uses as much as digits as its factorization.

196520017413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65506672474.

The product of its (nonzero) digits is 45360, while the sum is 39.

The spelling of 196520017413 in words is "one hundred ninety-six billion, five hundred twenty million, seventeen thousand, four hundred thirteen".

Divisors: 1 3 65506672471 196520017413