Base | Representation |
---|---|
bin | 1011011100000110000… |
… | …0010111111000000101 |
3 | 200210020211002020211110 |
4 | 2313001200113320011 |
5 | 11204433111024123 |
6 | 230140253555233 |
7 | 20124643405116 |
oct | 2670140277005 |
9 | 623224066743 |
10 | 196520017413 |
11 | 76386476835 |
12 | 321061a5b19 |
13 | 156bb370b95 |
14 | 9723c5420d |
15 | 51a2bbd493 |
hex | 2dc1817e05 |
196520017413 has 4 divisors (see below), whose sum is σ = 262026689888. Its totient is φ = 131013344940.
The previous prime is 196520017411. The next prime is 196520017429. The reversal of 196520017413 is 314710025691.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 196520017413 - 21 = 196520017411 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (196520017411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32753336233 + ... + 32753336238.
It is an arithmetic number, because the mean of its divisors is an integer number (65506672472).
Almost surely, 2196520017413 is an apocalyptic number.
It is an amenable number.
196520017413 is a deficient number, since it is larger than the sum of its proper divisors (65506672475).
196520017413 is an equidigital number, since it uses as much as digits as its factorization.
196520017413 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65506672474.
The product of its (nonzero) digits is 45360, while the sum is 39.
The spelling of 196520017413 in words is "one hundred ninety-six billion, five hundred twenty million, seventeen thousand, four hundred thirteen".
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