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19791119953 = 113541508103
BaseRepresentation
bin10010011011101001…
…001000011001010001
31220002021111001200201
4102123221020121101
5311013011314303
613031504215201
71300304513113
oct223351103121
956067431621
1019791119953
118436631390
123a0400a501
131b35331787
14d5a6713b3
157ac75a81d
hex49ba48651

19791119953 has 8 divisors (see below), whose sum is σ = 21596452416. Its totient is φ = 17986810800.

The previous prime is 19791119923. The next prime is 19791119969. The reversal of 19791119953 is 35991119791.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 19791119953 - 229 = 19254249041 is a prime.

It is a super-4 number, since 4×197911199534 (a number of 42 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 19791119894 and 19791119903.

It is not an unprimeable number, because it can be changed into a prime (19791119903) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 215101 + ... + 293002.

It is an arithmetic number, because the mean of its divisors is an integer number (2699556552).

Almost surely, 219791119953 is an apocalyptic number.

It is an amenable number.

19791119953 is a deficient number, since it is larger than the sum of its proper divisors (1805332463).

19791119953 is a wasteful number, since it uses less digits than its factorization.

19791119953 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 511655.

The product of its digits is 688905, while the sum is 55.

The spelling of 19791119953 in words is "nineteen billion, seven hundred ninety-one million, one hundred nineteen thousand, nine hundred fifty-three".

Divisors: 1 11 3541 38951 508103 5589133 1799192723 19791119953