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1980394137451 = 3366675882353
BaseRepresentation
bin11100110100011000101…
…100000110011101101011
321000022202001221211122201
4130310120230012131223
5224421321344344301
64113440331201031
7263036004264652
oct34643054063553
97008661854581
101980394137451
116a39759530a4
1227b991ba6177
1311499a727782
146bbcca84199
15367abb68201
hex1cd18b0676b

1980394137451 has 4 divisors (see below), whose sum is σ = 1980400356472. Its totient is φ = 1980387918432.

The previous prime is 1980394137437. The next prime is 1980394137457. The reversal of 1980394137451 is 1547314930891.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1980394137451 - 215 = 1980394104683 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1980394137392 and 1980394137401.

It is not an unprimeable number, because it can be changed into a prime (1980394137457) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2604510 + ... + 3277843.

It is an arithmetic number, because the mean of its divisors is an integer number (495100089118).

Almost surely, 21980394137451 is an apocalyptic number.

1980394137451 is a deficient number, since it is larger than the sum of its proper divisors (6219021).

1980394137451 is an equidigital number, since it uses as much as digits as its factorization.

1980394137451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6219020.

The product of its (nonzero) digits is 3265920, while the sum is 55.

The spelling of 1980394137451 in words is "one trillion, nine hundred eighty billion, three hundred ninety-four million, one hundred thirty-seven thousand, four hundred fifty-one".

Divisors: 1 336667 5882353 1980394137451