Base | Representation |
---|---|
bin | 11100110100011000101… |
… | …100000110011100111001 |
3 | 21000022202001221211120212 |
4 | 130310120230012130321 |
5 | 224421321344344101 |
6 | 4113440331200505 |
7 | 263036004264551 |
oct | 34643054063471 |
9 | 7008661854525 |
10 | 1980394137401 |
11 | 6a3975953059 |
12 | 27b991ba6135 |
13 | 11499a727744 |
14 | 6bbcca84161 |
15 | 367abb681bb |
hex | 1cd18b06739 |
1980394137401 has 2 divisors, whose sum is σ = 1980394137402. Its totient is φ = 1980394137400.
The previous prime is 1980394137383. The next prime is 1980394137431. The reversal of 1980394137401 is 1047314930891.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1944588415225 + 35805722176 = 1394485^2 + 189224^2 .
It is a cyclic number.
It is not a de Polignac number, because 1980394137401 - 222 = 1980389943097 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1980394137401.
It is not a weakly prime, because it can be changed into another prime (1980394137431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 990197068700 + 990197068701.
It is an arithmetic number, because the mean of its divisors is an integer number (990197068701).
Almost surely, 21980394137401 is an apocalyptic number.
It is an amenable number.
1980394137401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1980394137401 is an equidigital number, since it uses as much as digits as its factorization.
1980394137401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 653184, while the sum is 50.
The spelling of 1980394137401 in words is "one trillion, nine hundred eighty billion, three hundred ninety-four million, one hundred thirty-seven thousand, four hundred one".
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