1980937098145 has 4 divisors (see below), whose sum is σ = 2377124517780. Its totient is φ = 1584749678512.

The previous prime is 1980937098059. The next prime is 1980937098157. The reversal of 1980937098145 is 5418907390891.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 539302234384 + 1441634863761 = 734372^2 + 1200681^2 .

It is a cyclic number.

It is not a de Polignac number, because 1980937098145 - 2¹⁵ = 1980937065377 is a prime.

It is a super-3 number, since 3×1980937098145³ (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 198093709810 + ... + 198093709819.

It is an arithmetic number, because the mean of its divisors is an integer number (594281129445).

Almost surely, 2^{1980937098145} is an apocalyptic number.

It is an amenable number.

1980937098145 is a deficient number, since it is larger than the sum of its proper divisors (396187419635).

1980937098145 is an equidigital number, since it uses as much as digits as its factorization.

1980937098145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 396187419634.

The product of its (nonzero) digits is 19595520, while the sum is 64.

The spelling of 1980937098145 in words is "one trillion, nine hundred eighty billion, nine hundred thirty-seven million, ninety-eight thousand, one hundred forty-five".