Base | Representation |
---|---|
bin | 10010011100110001… |
… | …001001111010101001 |
3 | 1220010121000022000012 |
4 | 102130301021322221 |
5 | 311032330004203 |
6 | 13033421021305 |
7 | 1300624140440 |
oct | 223461117251 |
9 | 56117008005 |
10 | 19810000553 |
11 | 8446257692 |
12 | 3a0a3b4835 |
13 | 1b39212525 |
14 | d5cd87d57 |
15 | 7ae239bd8 |
hex | 49cc49ea9 |
19810000553 has 8 divisors (see below), whose sum is σ = 22642351872. Its totient is φ = 16978237056.
The previous prime is 19810000489. The next prime is 19810000589. The reversal of 19810000553 is 35500001891.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 19810000553 - 26 = 19810000489 is a prime.
It is a super-2 number, since 2×198100005532 (a number of 21 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (19810060553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 72200 + ... + 211737.
It is an arithmetic number, because the mean of its divisors is an integer number (2830293984).
Almost surely, 219810000553 is an apocalyptic number.
It is an amenable number.
19810000553 is a deficient number, since it is larger than the sum of its proper divisors (2832351319).
19810000553 is an equidigital number, since it uses as much as digits as its factorization.
19810000553 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 293911.
The product of its (nonzero) digits is 5400, while the sum is 32.
The spelling of 19810000553 in words is "nineteen billion, eight hundred ten million, five hundred fifty-three", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •