Base | Representation |
---|---|
bin | 1001000000100111000111… |
… | …11011000111111010000011 |
3 | 2121011000210012021101100201 |
4 | 10200103203323013322003 |
5 | 10044100403023033232 |
6 | 110045334405030031 |
7 | 4113246052461640 |
oct | 440234373077203 |
9 | 77130705241321 |
10 | 19812213096067 |
11 | 6349348875767 |
12 | 227b8a60b5317 |
13 | b0938c31a532 |
14 | 4c6cb81c8dc7 |
15 | 245563c26be7 |
hex | 1204e3ec7e83 |
19812213096067 has 16 divisors (see below), whose sum is σ = 23259251930112. Its totient is φ = 16522428303360.
The previous prime is 19812213096061. The next prime is 19812213096077. The reversal of 19812213096067 is 76069031221891.
It is a happy number.
It is a de Polignac number, because none of the positive numbers 2k-19812213096067 is a prime.
It is a super-3 number, since 3×198122130960673 (a number of 41 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 19812213095999 and 19812213096017.
It is not an unprimeable number, because it can be changed into a prime (19812213096061) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 127979659 + ... + 128134372.
It is an arithmetic number, because the mean of its divisors is an integer number (1453703245632).
Almost surely, 219812213096067 is an apocalyptic number.
19812213096067 is a deficient number, since it is larger than the sum of its proper divisors (3447038834045).
19812213096067 is a wasteful number, since it uses less digits than its factorization.
19812213096067 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 256114338.
The product of its (nonzero) digits is 1959552, while the sum is 55.
The spelling of 19812213096067 in words is "nineteen trillion, eight hundred twelve billion, two hundred thirteen million, ninety-six thousand, sixty-seven".
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