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19813400100 = 223252133721237
BaseRepresentation
bin10010011100111110…
…000111111000100100
31220010211102000022100
4102130332013320210
5311034212300400
613034021532100
71300665056604
oct223476077044
956124360270
1019813400100
11844816982a
123a0b574030
131b39b329b0
14d5d5d0c04
157ae6ac100
hex49cf87e24

19813400100 has 324 divisors, whose sum is σ = 68793255804. Its totient is φ = 4741493760.

The previous prime is 19813400093. The next prime is 19813400143. The reversal of 19813400100 is 100431891.

It can be written as a sum of positive squares in 18 ways, for example, as 5125414464 + 14687985636 = 71592^2 + 121194^2 .

It is a super-3 number, since 3×198134001003 (a number of 32 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 107 ways as a sum of consecutive naturals, for example, 16016682 + ... + 16017918.

Almost surely, 219813400100 is an apocalyptic number.

19813400100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 19813400100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (34396627902).

19813400100 is an abundant number, since it is smaller than the sum of its proper divisors (48979855704).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

19813400100 is a wasteful number, since it uses less digits than its factorization.

19813400100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1344 (or 1297 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 27.

Adding to 19813400100 its reverse (100431891), we get a palindrome (19913831991).

The spelling of 19813400100 in words is "nineteen billion, eight hundred thirteen million, four hundred thousand, one hundred".