19814031241 has 4 divisors (see below), whose sum is σ = 19838166084. Its totient is φ = 19789896400.

The previous prime is 19814031239. The next prime is 19814031277. The reversal of 19814031241 is 14213041891.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 14519286016 + 5294745225 = 120496^2 + 72765^2 .

It is a cyclic number.

It is not a de Polignac number, because 19814031241 - 2¹ = 19814031239 is a prime.

It is a super-3 number, since 3×19814031241³ (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 19814031197 and 19814031206.

It is not an unprimeable number, because it can be changed into a prime (19814031221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12066190 + ... + 12067831.

It is an arithmetic number, because the mean of its divisors is an integer number (4959541521).

Almost surely, 2^19814031241 is an apocalyptic number.

It is an amenable number.

19814031241 is a deficient number, since it is larger than the sum of its proper divisors (24134843).

19814031241 is an equidigital number, since it uses as much as digits as its factorization.

19814031241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24134842.

The product of its (nonzero) digits is 6912, while the sum is 34.

The spelling of 19814031241 in words is "nineteen billion, eight hundred fourteen million, thirty-one thousand, two hundred forty-one".