Base | Representation |
---|---|
bin | 11100110101010101011… |
… | …011110111001101011011 |
3 | 21000102101002200012021122 |
4 | 130311111123313031123 |
5 | 224430413300301333 |
6 | 4114125415155455 |
7 | 263103161040440 |
oct | 34652533671533 |
9 | 7012332605248 |
10 | 1981413290843 |
11 | 6a4349169128 |
12 | 280017375b8b |
13 | 114b0090c90c |
14 | 6bc881799c7 |
15 | 3681b37e798 |
hex | 1cd556f735b |
1981413290843 has 16 divisors (see below), whose sum is σ = 2307294996480. Its totient is φ = 1666239939936.
The previous prime is 1981413290809. The next prime is 1981413290947. The reversal of 1981413290843 is 3480923141891.
It is a cyclic number.
It is not a de Polignac number, because 1981413290843 - 220 = 1981412242267 is a prime.
It is a super-3 number, since 3×19814132908433 (a number of 38 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (53).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1981413290743) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9965678 + ... + 10162556.
It is an arithmetic number, because the mean of its divisors is an integer number (144205937280).
Almost surely, 21981413290843 is an apocalyptic number.
1981413290843 is a deficient number, since it is larger than the sum of its proper divisors (325881705637).
1981413290843 is a wasteful number, since it uses less digits than its factorization.
1981413290843 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 224066.
The product of its (nonzero) digits is 1492992, while the sum is 53.
The spelling of 1981413290843 in words is "one trillion, nine hundred eighty-one billion, four hundred thirteen million, two hundred ninety thousand, eight hundred forty-three".
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