Base | Representation |
---|---|
bin | 1011100010010110010… |
… | …1100000000010001011 |
3 | 200221120211112122000020 |
4 | 2320211211200002023 |
5 | 11221402431130042 |
6 | 231015034111523 |
7 | 20214362260362 |
oct | 2704545400213 |
9 | 627524478006 |
10 | 198199083147 |
11 | 7706824076a |
12 | 324b457b5a3 |
13 | 158c819a9c0 |
14 | 9842c4a7d9 |
15 | 52502d93ec |
hex | 2e2596008b |
198199083147 has 32 divisors (see below), whose sum is σ = 294853634880. Its totient is φ = 117584248320.
The previous prime is 198199083113. The next prime is 198199083151. The reversal of 198199083147 is 741380991891.
It is not a de Polignac number, because 198199083147 - 26 = 198199083083 is a prime.
It is a super-2 number, since 2×1981990831472 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (198199083347) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 615033 + ... + 880149.
It is an arithmetic number, because the mean of its divisors is an integer number (9214176090).
Almost surely, 2198199083147 is an apocalyptic number.
198199083147 is a deficient number, since it is larger than the sum of its proper divisors (96654551733).
198199083147 is a wasteful number, since it uses less digits than its factorization.
198199083147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 265823.
The product of its (nonzero) digits is 3919104, while the sum is 60.
The spelling of 198199083147 in words is "one hundred ninety-eight billion, one hundred ninety-nine million, eighty-three thousand, one hundred forty-seven".
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