Base | Representation |
---|---|
bin | 10111101000011… |
… | …10011110101101 |
3 | 111211000122101122 |
4 | 23310032132231 |
5 | 401222141143 |
6 | 31400550325 |
7 | 4625004455 |
oct | 1364163655 |
9 | 454018348 |
10 | 198240173 |
11 | a19a085a |
12 | 564823a5 |
13 | 320bc2a1 |
14 | 1c484d65 |
15 | 1260cc68 |
hex | bd0e7ad |
198240173 has 4 divisors (see below), whose sum is σ = 199347840. Its totient is φ = 197132508.
The previous prime is 198240149. The next prime is 198240241. The reversal of 198240173 is 371042891.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 371042891 = 9521 ⋅38971.
It is a cyclic number.
It is not a de Polignac number, because 198240173 - 26 = 198240109 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (198240373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 553565 + ... + 553922.
It is an arithmetic number, because the mean of its divisors is an integer number (49836960).
Almost surely, 2198240173 is an apocalyptic number.
It is an amenable number.
198240173 is a deficient number, since it is larger than the sum of its proper divisors (1107667).
198240173 is a wasteful number, since it uses less digits than its factorization.
198240173 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1107666.
The product of its (nonzero) digits is 12096, while the sum is 35.
The square root of 198240173 is about 14079.7788690022. The cubic root of 198240173 is about 583.0832368623.
The spelling of 198240173 in words is "one hundred ninety-eight million, two hundred forty thousand, one hundred seventy-three".
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