Base | Representation |
---|---|
bin | 11100110111101101100… |
… | …101011110000100100100 |
3 | 21000122221222221112001201 |
4 | 130313231211132010210 |
5 | 230001130240234043 |
6 | 4115231003332244 |
7 | 263223345203254 |
oct | 34675545360444 |
9 | 7018858845051 |
10 | 1983965946148 |
11 | 6a543906690a |
12 | 28060a221084 |
13 | 115119716c44 |
14 | 6c04b1b5964 |
15 | 3691a50bc4d |
hex | 1cded95e124 |
1983965946148 has 12 divisors (see below), whose sum is σ = 3472529210892. Its totient is φ = 991814743040.
The previous prime is 1983965946143. The next prime is 1983965946181. The reversal of 1983965946148 is 8416495693891.
It can be written as a sum of positive squares in 2 ways, for example, as 1155177843264 + 828788102884 = 1074792^2 + 910378^2 .
It is a super-2 number, since 2×19839659461482 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1983965946143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42030973 + ... + 42078148.
It is an arithmetic number, because the mean of its divisors is an integer number (289377434241).
Almost surely, 21983965946148 is an apocalyptic number.
It is an amenable number.
1983965946148 is a deficient number, since it is larger than the sum of its proper divisors (1488563264744).
1983965946148 is a wasteful number, since it uses less digits than its factorization.
1983965946148 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 84115022 (or 84115020 counting only the distinct ones).
The product of its digits is 403107840, while the sum is 73.
The spelling of 1983965946148 in words is "one trillion, nine hundred eighty-three billion, nine hundred sixty-five million, nine hundred forty-six thousand, one hundred forty-eight".
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