Base | Representation |
---|---|
bin | 11101000000010000110… |
… | …100101010001010100111 |
3 | 21001112122211211200102122 |
4 | 131000100310222022213 |
5 | 230123431122034444 |
6 | 4123350014500155 |
7 | 264000020342516 |
oct | 35002064521247 |
9 | 7045584750378 |
10 | 1993147064999 |
11 | 6a931a614342 |
12 | 282350b0465b |
13 | 115c5087044c |
14 | 6c67c69667d |
15 | 36ca65634ee |
hex | 1d010d2a2a7 |
1993147064999 has 4 divisors (see below), whose sum is σ = 1996031504280. Its totient is φ = 1990262625720.
The previous prime is 1993147064977. The next prime is 1993147065011. The reversal of 1993147064999 is 9994607413991.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1993147064999 - 240 = 893635437223 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1993147064929) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1442218604 + ... + 1442219985.
It is an arithmetic number, because the mean of its divisors is an integer number (499007876070).
Almost surely, 21993147064999 is an apocalyptic number.
1993147064999 is a deficient number, since it is larger than the sum of its proper divisors (2884439281).
1993147064999 is an equidigital number, since it uses as much as digits as its factorization.
1993147064999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2884439280.
The product of its (nonzero) digits is 119042784, while the sum is 71.
The spelling of 1993147064999 in words is "one trillion, nine hundred ninety-three billion, one hundred forty-seven million, sixty-four thousand, nine hundred ninety-nine".
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