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19934049333 = 311604062101
BaseRepresentation
bin10010100100001010…
…010111010000110101
31220110020102121221110
4102210022113100311
5311311104034313
613054011505233
71303661423622
oct224412272065
956406377843
1019934049333
1184aa284340
123a43a58219
131b58b26283
14d71639349
157ba08eec3
hex4a4297435

19934049333 has 8 divisors (see below), whose sum is σ = 28994980896. Its totient is φ = 12081242000.

The previous prime is 19934049307. The next prime is 19934049341. The reversal of 19934049333 is 33394043991.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 19934049333 - 25 = 19934049301 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (19934045333) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 302031018 + ... + 302031083.

It is an arithmetic number, because the mean of its divisors is an integer number (3624372612).

Almost surely, 219934049333 is an apocalyptic number.

It is an amenable number.

19934049333 is a deficient number, since it is larger than the sum of its proper divisors (9060931563).

19934049333 is a wasteful number, since it uses less digits than its factorization.

19934049333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 604062115.

The product of its (nonzero) digits is 944784, while the sum is 48.

The spelling of 19934049333 in words is "nineteen billion, nine hundred thirty-four million, forty-nine thousand, three hundred thirty-three".

Divisors: 1 3 11 33 604062101 1812186303 6644683111 19934049333