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199702028921471 = 613273803752811
BaseRepresentation
bin101101011010000011000000…
…011111101010101001111111
3222012002022211202110220211222
4231122003000133222221333
5202133404223400441341
61544421502351103555
760030665305041116
oct5532030037525177
9865068752426758
10199702028921471
11586a417811785a
121a493711511bbb
138757a888c272b
1437458b6148c7d
151814a94aa744b
hexb5a0c07eaa7f

199702028921471 has 4 divisors (see below), whose sum is σ = 202975832674344. Its totient is φ = 196428225168600.

The previous prime is 199702028921453. The next prime is 199702028921491. The reversal of 199702028921471 is 174129820207991.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-199702028921471 is a prime.

It is a super-3 number, since 3×1997020289214713 (a number of 44 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (199702028921491) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1636901876345 + ... + 1636901876466.

It is an arithmetic number, because the mean of its divisors is an integer number (50743958168586).

Almost surely, 2199702028921471 is an apocalyptic number.

199702028921471 is a deficient number, since it is larger than the sum of its proper divisors (3273803752873).

199702028921471 is an equidigital number, since it uses as much as digits as its factorization.

199702028921471 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3273803752872.

The product of its (nonzero) digits is 9144576, while the sum is 62.

The spelling of 199702028921471 in words is "one hundred ninety-nine trillion, seven hundred two billion, twenty-eight million, nine hundred twenty-one thousand, four hundred seventy-one".

Divisors: 1 61 3273803752811 199702028921471