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199861955583400 = 23521159101149102317
BaseRepresentation
bin101101011100010111111100…
…110111011101110110101000
3222012122121122022201002221001
4231130113330313131312220
5202144014241112132100
61545023152002324344
760045356401165525
oct5534277467356650
9865577568632831
10199861955583400
1158755a85599a40
121a4ba7046596b4
138769b948c2336
14374d52800c14c
151818d04da9d6a
hexb5c5fcdddda8

199861955583400 has 384 divisors, whose sum is σ = 524117815920000. Its totient is φ = 70262443520000.

The previous prime is 199861955583391. The next prime is 199861955583443. The reversal of 199861955583400 is 4385559168991.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1953309042 + ... + 1953411358.

It is an arithmetic number, because the mean of its divisors is an integer number (1364890145625).

Almost surely, 2199861955583400 is an apocalyptic number.

199861955583400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 199861955583400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (262058907960000).

199861955583400 is an abundant number, since it is smaller than the sum of its proper divisors (324255860336600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

199861955583400 is a wasteful number, since it uses less digits than its factorization.

199861955583400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 102653 (or 102644 counting only the distinct ones).

The product of its (nonzero) digits is 419904000, while the sum is 73.

The spelling of 199861955583400 in words is "one hundred ninety-nine trillion, eight hundred sixty-one billion, nine hundred fifty-five million, five hundred eighty-three thousand, four hundred".