Base | Representation |
---|---|
bin | 10010100111100001… |
… | …000110111000011011 |
3 | 1220121011100122121022 |
4 | 102213201012320123 |
5 | 311420011440240 |
6 | 13103342233055 |
7 | 1305244053644 |
oct | 224741067033 |
9 | 56534318538 |
10 | 19990343195 |
11 | 8529033799 |
12 | 3a5a88578b |
13 | 1b676a6354 |
14 | d78cd06cb |
15 | 7beeae9b5 |
hex | 4a7846e1b |
19990343195 has 8 divisors (see below), whose sum is σ = 24004596336. Its totient is φ = 15981484896.
The previous prime is 19990343183. The next prime is 19990343209. The reversal of 19990343195 is 59134309991.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 19990343195 - 212 = 19990339099 is a prime.
It is a super-2 number, since 2×199903431952 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1340552 + ... + 1355381.
It is an arithmetic number, because the mean of its divisors is an integer number (3000574542).
Almost surely, 219990343195 is an apocalyptic number.
19990343195 is a deficient number, since it is larger than the sum of its proper divisors (4014253141).
19990343195 is a wasteful number, since it uses less digits than its factorization.
19990343195 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2697421.
The product of its (nonzero) digits is 1180980, while the sum is 53.
The spelling of 19990343195 in words is "nineteen billion, nine hundred ninety million, three hundred forty-three thousand, one hundred ninety-five".
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