Base | Representation |
---|---|
bin | 11101000110000010111… |
… | …011011111000111111111 |
3 | 21002010200120211211121222 |
4 | 131012002323133013333 |
5 | 230224140221042303 |
6 | 4130254110543555 |
7 | 264306626130161 |
oct | 35060273370777 |
9 | 7063616754558 |
10 | 1999356424703 |
11 | 700a16640180 |
12 | 2835a4507bbb |
13 | 11670011c7a1 |
14 | 6caab202931 |
15 | 3701b753938 |
hex | 1d182edf1ff |
1999356424703 has 8 divisors (see below), whose sum is σ = 2187996595920. Its totient is φ = 1811863002880.
The previous prime is 1999356424657. The next prime is 1999356424717. The reversal of 1999356424703 is 3074246539991.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1999356424703 - 216 = 1999356359167 is a prime.
It is a super-2 number, since 2×19993564247032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1999356424733) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 286683698 + ... + 286690671.
It is an arithmetic number, because the mean of its divisors is an integer number (273499574490).
Almost surely, 21999356424703 is an apocalyptic number.
1999356424703 is a deficient number, since it is larger than the sum of its proper divisors (188640171217).
1999356424703 is a wasteful number, since it uses less digits than its factorization.
1999356424703 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 573374697.
The product of its (nonzero) digits is 44089920, while the sum is 62.
The spelling of 1999356424703 in words is "one trillion, nine hundred ninety-nine billion, three hundred fifty-six million, four hundred twenty-four thousand, seven hundred three".
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