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199941035 = 575712601
BaseRepresentation
bin10111110101011…
…01101110101011
3111221020001112112
423322231232223
5402141103120
631501232535
74645320320
oct1372555653
9457201475
10199941035
11a2952728
1256b6274b
1332566508
141c7a8b47
1512846bc5
hexbeadbab

199941035 has 8 divisors (see below), whose sum is σ = 274204896. Its totient is φ = 137102400.

The previous prime is 199941019. The next prime is 199941073. The reversal of 199941035 is 530149991.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 199941035 - 24 = 199941019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 199940983 and 199941001.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2856266 + ... + 2856335.

It is an arithmetic number, because the mean of its divisors is an integer number (34275612).

Almost surely, 2199941035 is an apocalyptic number.

199941035 is a deficient number, since it is larger than the sum of its proper divisors (74263861).

199941035 is an equidigital number, since it uses as much as digits as its factorization.

199941035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5712613.

The product of its (nonzero) digits is 43740, while the sum is 41.

The square root of 199941035 is about 14140.0507424832. The cubic root of 199941035 is about 584.7460704250.

It can be divided in two parts, 1999 and 41035, that added together give a palindrome (43034).

The spelling of 199941035 in words is "one hundred ninety-nine million, nine hundred forty-one thousand, thirty-five".

Divisors: 1 5 7 35 5712601 28563005 39988207 199941035