1999411799112 has 384 divisors, whose sum is σ = 6887696025600. Its totient is φ = 526201857792.

The previous prime is 1999411799093. The next prime is 1999411799113. The reversal of 1999411799112 is 2119971149991.

1999411799112 is a `hidden beast` number, since 19 + 9 + 9 + 411 + 7 + 99 + 112 = 666.

It is a Harshad number since it is a multiple of its sum of digits (63).

It is a nude number because it is divisible by every one of its digits.

It is a self number, because there is not a number n which added to its sum of digits gives 1999411799112.

It is not an unprimeable number, because it can be changed into a prime (1999411799113) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 124434103 + ... + 124450169.

It is an arithmetic number, because the mean of its divisors is an integer number (17936708400).

Almost surely, 2^{1999411799112} is an apocalyptic number.

1999411799112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1999411799112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3443848012800).

1999411799112 is an abundant number, since it is smaller than the sum of its proper divisors (4888284226488).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1999411799112 is a wasteful number, since it uses less digits than its factorization.

1999411799112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16602 (or 16579 counting only the distinct ones).

The product of its digits is 3306744, while the sum is 63.

The spelling of 1999411799112 in words is "one trillion, nine hundred ninety-nine billion, four hundred eleven million, seven hundred ninety-nine thousand, one hundred twelve".