Base | Representation |
---|---|
bin | 10010100111111001… |
… | …110001100001010111 |
3 | 1220121121112011102210 |
4 | 102213321301201113 |
5 | 311423140344203 |
6 | 13104133004503 |
7 | 1305353034402 |
oct | 224771614127 |
9 | 56547464383 |
10 | 19996809303 |
11 | 853174a889 |
12 | 3a60a83733 |
13 | 1b68b2b553 |
14 | d79ad4d39 |
15 | 7c083a803 |
hex | 4a7e71857 |
19996809303 has 4 divisors (see below), whose sum is σ = 26662412408. Its totient is φ = 13331206200.
The previous prime is 19996809277. The next prime is 19996809307. The reversal of 19996809303 is 30390869991.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30390869991 = 3 ⋅10130289997.
It is not a de Polignac number, because 19996809303 - 29 = 19996808791 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (19996809307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3332801548 + ... + 3332801553.
It is an arithmetic number, because the mean of its divisors is an integer number (6665603102).
Almost surely, 219996809303 is an apocalyptic number.
19996809303 is a deficient number, since it is larger than the sum of its proper divisors (6665603105).
19996809303 is an equidigital number, since it uses as much as digits as its factorization.
19996809303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6665603104.
The product of its (nonzero) digits is 2834352, while the sum is 57.
The spelling of 19996809303 in words is "nineteen billion, nine hundred ninety-six million, eight hundred nine thousand, three hundred three".
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