Base | Representation |
---|---|
bin | 101101011110011001100011… |
… | …001011101011010110111111 |
3 | 222020010220211022101100110111 |
4 | 231132121203023223112333 |
5 | 202203304233421023403 |
6 | 1545211124140250451 |
7 | 60061413656515501 |
oct | 5536314313532677 |
9 | 866126738340414 |
10 | 200001111111103 |
11 | 587a9aa4227595 |
12 | 1a52167b540a27 |
13 | 877a040530083 |
14 | 3756169415d71 |
15 | 181c74b8bc56d |
hex | b5e6632eb5bf |
200001111111103 has 4 divisors (see below), whose sum is σ = 200001144164328. Its totient is φ = 200001078057880.
The previous prime is 200001111111083. The next prime is 200001111111107. The reversal of 200001111111103 is 301111111100002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 200001111111103 - 217 = 200001110980031 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200001111111107) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4563913 + ... + 20514178.
It is an arithmetic number, because the mean of its divisors is an integer number (50000286041082).
Almost surely, 2200001111111103 is an apocalyptic number.
200001111111103 is a deficient number, since it is larger than the sum of its proper divisors (33053225).
200001111111103 is an equidigital number, since it uses as much as digits as its factorization.
200001111111103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33053224.
The product of its (nonzero) digits is 6, while the sum is 13.
Adding to 200001111111103 its reverse (301111111100002), we get a palindrome (501112222211105).
The spelling of 200001111111103 in words is "two hundred trillion, one billion, one hundred eleven million, one hundred eleven thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.105 sec. • engine limits •