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200003111213 = 594073366659
BaseRepresentation
bin1011101001000100011…
…1010100100100101101
3201010020120010202021112
42322101013110210231
511234101244024323
6231514040441405
720310156252413
oct2722107244455
9633216122245
10200003111213
11779035a6754
1232918779265
1315b24b6b329
1499746912b3
15530888b178
hex2e911d492d

200003111213 has 4 divisors (see below), whose sum is σ = 200006537280. Its totient is φ = 199999685148.

The previous prime is 200003111179. The next prime is 200003111239. The reversal of 200003111213 is 312111300002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200003111213 - 230 = 198929369389 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200003111263) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1623923 + ... + 1742736.

It is an arithmetic number, because the mean of its divisors is an integer number (50001634320).

Almost surely, 2200003111213 is an apocalyptic number.

It is an amenable number.

200003111213 is a deficient number, since it is larger than the sum of its proper divisors (3426067).

200003111213 is an equidigital number, since it uses as much as digits as its factorization.

200003111213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3426066.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 200003111213 its reverse (312111300002), we get a palindrome (512114411215).

The spelling of 200003111213 in words is "two hundred billion, three million, one hundred eleven thousand, two hundred thirteen".

Divisors: 1 59407 3366659 200003111213