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2000031223111 = 5993338950289
BaseRepresentation
bin11101000110101011001…
…001101000110101000111
321002012102121121011000121
4131012223021220311013
5230232030443114421
64130445054122411
7264332431616365
oct35065311506507
97065377534017
102000031223111
11701232537209
122837524b0407
131167a9b76c9c
146cb32a9a635
153705aae8d41
hex1d1ab268d47

2000031223111 has 4 divisors (see below), whose sum is σ = 2003370174000. Its totient is φ = 1996692272224.

The previous prime is 2000031223079. The next prime is 2000031223139. The reversal of 2000031223111 is 1113221300002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2000031223111 - 25 = 2000031223079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2000031223181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1669474546 + ... + 1669475743.

It is an arithmetic number, because the mean of its divisors is an integer number (500842543500).

Almost surely, 22000031223111 is an apocalyptic number.

2000031223111 is a deficient number, since it is larger than the sum of its proper divisors (3338950889).

2000031223111 is an equidigital number, since it uses as much as digits as its factorization.

2000031223111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3338950888.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 2000031223111 its reverse (1113221300002), we get a palindrome (3113252523113).

The spelling of 2000031223111 in words is "two trillion, thirty-one million, two hundred twenty-three thousand, one hundred eleven".

Divisors: 1 599 3338950289 2000031223111