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200003303320114 = 2714285950237151
BaseRepresentation
bin101101011110011011100101…
…110110010010101000110010
3222020011010111002102002212211
4231132123211312102220302
5202203323231122220424
61545212125451042334
760061522206135430
oct5536334566225062
9866133432362784
10200003303320114
11587aaa19715678
121a521b917403aa
13877a2cc764478
1437562d6625d50
15181c82909ab94
hexb5e6e5d92a32

200003303320114 has 8 divisors (see below), whose sum is σ = 342862805691648. Its totient is φ = 85715701422900.

The previous prime is 200003303320103. The next prime is 200003303320123. The reversal of 200003303320114 is 411023303300002.

200003303320114 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7142975118562 + ... + 7142975118589.

It is an arithmetic number, because the mean of its divisors is an integer number (42857850711456).

Almost surely, 2200003303320114 is an apocalyptic number.

200003303320114 is a deficient number, since it is larger than the sum of its proper divisors (142859502371534).

200003303320114 is a wasteful number, since it uses less digits than its factorization.

200003303320114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14285950237160.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 200003303320114 its reverse (411023303300002), we get a palindrome (611026606620116).

The spelling of 200003303320114 in words is "two hundred trillion, three billion, three hundred three million, three hundred twenty thousand, one hundred fourteen".

Divisors: 1 2 7 14 14285950237151 28571900474302 100001651660057 200003303320114