Base | Representation |
---|---|
bin | 11101000110101111011… |
… | …011111000000110101011 |
3 | 21002012121121212112120221 |
4 | 131012233123320012223 |
5 | 230232202344110011 |
6 | 4130500143030511 |
7 | 264334263644314 |
oct | 35065733700653 |
9 | 7065547775527 |
10 | 2000103113131 |
11 | 70126a079252 |
12 | 28377259b437 |
13 | 1167bba27b66 |
14 | 6cb3c45160b |
15 | 37062099971 |
hex | 1d1af6f81ab |
2000103113131 has 16 divisors (see below), whose sum is σ = 2040526474560. Its totient is φ = 1960166707200.
The previous prime is 2000103113123. The next prime is 2000103113243. The reversal of 2000103113131 is 1313113010002.
It is a cyclic number.
It is not a de Polignac number, because 2000103113131 - 23 = 2000103113123 is a prime.
It is a super-3 number, since 3×20001031131313 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2000103113531) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4427715 + ... + 4858483.
It is an arithmetic number, because the mean of its divisors is an integer number (127532904660).
Almost surely, 22000103113131 is an apocalyptic number.
2000103113131 is a deficient number, since it is larger than the sum of its proper divisors (40423361429).
2000103113131 is a wasteful number, since it uses less digits than its factorization.
2000103113131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 431334.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 2000103113131 its reverse (1313113010002), we get a palindrome (3313216123133).
The spelling of 2000103113131 in words is "two trillion, one hundred three million, one hundred thirteen thousand, one hundred thirty-one".
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