Base | Representation |
---|---|
bin | 101101011110100010110111… |
… | …110100110101011101010111 |
3 | 222020011212122220222112201220 |
4 | 231132202313310311131113 |
5 | 202203440234001333421 |
6 | 1545215501321421423 |
7 | 60062220015301236 |
oct | 5536426764653527 |
9 | 866155586875656 |
10 | 200011121121111 |
11 | 58803270659233 |
12 | 1a5235b393a873 |
13 | 877ac77313811 |
14 | 3756838a22b1d |
15 | 181cb355a63c6 |
hex | b5e8b7d35757 |
200011121121111 has 8 divisors (see below), whose sum is σ = 271053322612464. Its totient is φ = 131154833521920.
The previous prime is 200011121121079. The next prime is 200011121121157. The reversal of 200011121121111 is 111121121110002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 200011121121111 - 25 = 200011121121079 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200011121121811) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 546478472826 + ... + 546478473191.
It is an arithmetic number, because the mean of its divisors is an integer number (33881665326558).
Almost surely, 2200011121121111 is an apocalyptic number.
200011121121111 is a deficient number, since it is larger than the sum of its proper divisors (71042201491353).
200011121121111 is a wasteful number, since it uses less digits than its factorization.
200011121121111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1092956946081.
The product of its (nonzero) digits is 8, while the sum is 15.
Adding to 200011121121111 its reverse (111121121110002), we get a palindrome (311132242231113).
The spelling of 200011121121111 in words is "two hundred trillion, eleven billion, one hundred twenty-one million, one hundred twenty-one thousand, one hundred eleven".
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