200012102441301 has 4 divisors (see below), whose sum is σ = 266682803255072. Its totient is φ = 133341401627532.

The previous prime is 200012102441293. The next prime is 200012102441309. The reversal of 200012102441301 is 103144201210002.

200012102441301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (200012102441293) and next prime (200012102441309).

It is not a de Polignac number, because 200012102441301 - 2³ = 200012102441293 is a prime.

It is a super-2 number, since 2×200012102441301² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200012102441309) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33335350406881 + ... + 33335350406886.

It is an arithmetic number, because the mean of its divisors is an integer number (66670700813768).

Almost surely, 2^{200012102441301} is an apocalyptic number.

It is an amenable number.

200012102441301 is a deficient number, since it is larger than the sum of its proper divisors (66670700813771).

200012102441301 is an equidigital number, since it uses as much as digits as its factorization.

200012102441301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66670700813770.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 200012102441301 its reverse (103144201210002), we get a palindrome (303156303651303).

The spelling of 200012102441301 in words is "two hundred trillion, twelve billion, one hundred two million, four hundred forty-one thousand, three hundred one".