Base | Representation |
---|---|
bin | 11101000110110000100… |
… | …001101000101100100111 |
3 | 21002012122220021121121012 |
4 | 131012300201220230213 |
5 | 230232222034300403 |
6 | 4130502035012435 |
7 | 264334605250151 |
oct | 35066041505447 |
9 | 7065586247535 |
10 | 2000121400103 |
11 | 701279429552 |
12 | 28377873a11b |
13 | 1167c275b658 |
14 | 6cb40a51ad1 |
15 | 370639aced8 |
hex | 1d1b0868b27 |
2000121400103 has 4 divisors (see below), whose sum is σ = 2048904848928. Its totient is φ = 1951337951280.
The previous prime is 2000121400091. The next prime is 2000121400111. The reversal of 2000121400103 is 3010041210002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2000121400103 - 210 = 2000121399079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2000151400103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24391724351 + ... + 24391724432.
It is an arithmetic number, because the mean of its divisors is an integer number (512226212232).
Almost surely, 22000121400103 is an apocalyptic number.
2000121400103 is a deficient number, since it is larger than the sum of its proper divisors (48783448825).
2000121400103 is an equidigital number, since it uses as much as digits as its factorization.
2000121400103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48783448824.
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 2000121400103 its reverse (3010041210002), we get a palindrome (5010162610105).
The spelling of 2000121400103 in words is "two trillion, one hundred twenty-one million, four hundred thousand, one hundred three".
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