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200013011010303 = 366671003670101
BaseRepresentation
bin101101011110100100101000…
…011110001100001011111111
3222020012001112122010212022220
4231132210220132030023333
5202204003121304312203
61545220413032340423
760062314604140251
oct5536445036141377
9866161478125286
10200013011010303
1158804050428a27
121a523a40844713
13877b1b8a1724a
143756977a17cd1
15181cbe6468653
hexb5e92878c2ff

200013011010303 has 4 divisors (see below), whose sum is σ = 266684014680408. Its totient is φ = 133342007340200.

The previous prime is 200013011010277. The next prime is 200013011010413. The reversal of 200013011010303 is 303010110310002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200013011010303 - 216 = 200013010944767 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200013016010303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33335501835048 + ... + 33335501835053.

It is an arithmetic number, because the mean of its divisors is an integer number (66671003670102).

Almost surely, 2200013011010303 is an apocalyptic number.

200013011010303 is a deficient number, since it is larger than the sum of its proper divisors (66671003670105).

200013011010303 is an equidigital number, since it uses as much as digits as its factorization.

200013011010303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66671003670104.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 200013011010303 its reverse (303010110310002), we get a palindrome (503023121320305).

The spelling of 200013011010303 in words is "two hundred trillion, thirteen billion, eleven million, ten thousand, three hundred three".

Divisors: 1 3 66671003670101 200013011010303