Base | Representation |
---|---|
bin | 101101011110100100101000… |
… | …011110001100001011111111 |
3 | 222020012001112122010212022220 |
4 | 231132210220132030023333 |
5 | 202204003121304312203 |
6 | 1545220413032340423 |
7 | 60062314604140251 |
oct | 5536445036141377 |
9 | 866161478125286 |
10 | 200013011010303 |
11 | 58804050428a27 |
12 | 1a523a40844713 |
13 | 877b1b8a1724a |
14 | 3756977a17cd1 |
15 | 181cbe6468653 |
hex | b5e92878c2ff |
200013011010303 has 4 divisors (see below), whose sum is σ = 266684014680408. Its totient is φ = 133342007340200.
The previous prime is 200013011010277. The next prime is 200013011010413. The reversal of 200013011010303 is 303010110310002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 200013011010303 - 216 = 200013010944767 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200013016010303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33335501835048 + ... + 33335501835053.
It is an arithmetic number, because the mean of its divisors is an integer number (66671003670102).
Almost surely, 2200013011010303 is an apocalyptic number.
200013011010303 is a deficient number, since it is larger than the sum of its proper divisors (66671003670105).
200013011010303 is an equidigital number, since it uses as much as digits as its factorization.
200013011010303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66671003670104.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 200013011010303 its reverse (303010110310002), we get a palindrome (503023121320305).
The spelling of 200013011010303 in words is "two hundred trillion, thirteen billion, eleven million, ten thousand, three hundred three".
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