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200013110112003 = 366671036704001
BaseRepresentation
bin101101011110100100101110…
…011000001110111100000011
3222020012001210112121202022020
4231132210232120032330003
5202204003322142041003
61545220430532412523
760062320216401426
oct5536445630167403
9866161715552266
10200013110112003
11588040a1366561
121a523a69a77143
13877b203404bc6
143756986c539bd
15181cbeeee1d53
hexb5e92e60ef03

200013110112003 has 4 divisors (see below), whose sum is σ = 266684146816008. Its totient is φ = 133342073408000.

The previous prime is 200013110111887. The next prime is 200013110112031. The reversal of 200013110112003 is 300211011310002.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200013110112003 - 225 = 200013076557571 is a prime.

It is not an unprimeable number, because it can be changed into a prime (200013110112103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33335518351998 + ... + 33335518352003.

It is an arithmetic number, because the mean of its divisors is an integer number (66671036704002).

Almost surely, 2200013110112003 is an apocalyptic number.

200013110112003 is a deficient number, since it is larger than the sum of its proper divisors (66671036704005).

200013110112003 is an equidigital number, since it uses as much as digits as its factorization.

200013110112003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66671036704004.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 200013110112003 its reverse (300211011310002), we get a palindrome (500224121422005).

The spelling of 200013110112003 in words is "two hundred trillion, thirteen billion, one hundred ten million, one hundred twelve thousand, three".

Divisors: 1 3 66671036704001 200013110112003