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200013200002015 = 540002640000403
BaseRepresentation
bin101101011110100100110011…
…101111001000101111011111
3222020012002000210202122012221
4231132210303233020233133
5202204004013200031030
61545220443503210211
760062322360425431
oct5536446357105737
9866162023678187
10200013200002015
1158804138082224
121a523a93ba6967
13877b218c18a6a
143756994b72651
15181cc07d4ae7a
hexb5e933bc8bdf

200013200002015 has 4 divisors (see below), whose sum is σ = 240015840002424. Its totient is φ = 160010560001608.

The previous prime is 200013200001899. The next prime is 200013200002043. The reversal of 200013200002015 is 510200002310002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200013200002015 - 213 = 200013199993823 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 200013200002015.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20001320000197 + ... + 20001320000206.

It is an arithmetic number, because the mean of its divisors is an integer number (60003960000606).

Almost surely, 2200013200002015 is an apocalyptic number.

200013200002015 is a deficient number, since it is larger than the sum of its proper divisors (40002640000409).

200013200002015 is an equidigital number, since it uses as much as digits as its factorization.

200013200002015 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40002640000408.

The product of its (nonzero) digits is 120, while the sum is 16.

Adding to 200013200002015 its reverse (510200002310002), we get a palindrome (710213202312017).

The spelling of 200013200002015 in words is "two hundred trillion, thirteen billion, two hundred million, two thousand, fifteen".

Divisors: 1 5 40002640000403 200013200002015