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2000132505551 = 14737135721823
BaseRepresentation
bin11101000110110001001…
…011111111111111001111
321002012200200011211102002
4131012301023333333033
5230232232410134201
64130503113022515
7264335101532435
oct35066113777717
97065620154362
102000132505551
11701284724204
122837803b4a3b
131167c4b4941b
146cb42302d55
153706495376b
hex1d1b12fffcf

2000132505551 has 4 divisors (see below), whose sum is σ = 2000268242112. Its totient is φ = 1999996768992.

The previous prime is 2000132505541. The next prime is 2000132505577. The reversal of 2000132505551 is 1555052310002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2000132505551 - 218 = 2000132243407 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2000132505541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67846175 + ... + 67875648.

It is an arithmetic number, because the mean of its divisors is an integer number (500067060528).

Almost surely, 22000132505551 is an apocalyptic number.

2000132505551 is a deficient number, since it is larger than the sum of its proper divisors (135736561).

2000132505551 is a wasteful number, since it uses less digits than its factorization.

2000132505551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 135736560.

The product of its (nonzero) digits is 7500, while the sum is 29.

Adding to 2000132505551 its reverse (1555052310002), we get a palindrome (3555184815553).

The spelling of 2000132505551 in words is "two trillion, one hundred thirty-two million, five hundred five thousand, five hundred fifty-one".

Divisors: 1 14737 135721823 2000132505551